x^2+64-16x-96=160

Solution for x^2+64-16x-96=160 equation:

x^2+64-16x-96=160

We move all terms to the left:

x^2+64-16x-96-(160)=0

We add all the numbers together, and all the variables

x^2-16x-192=0

a = 1; b = -16; c = -192;
Δ = b2-4ac
Δ = -162-4·1·(-192)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-32}{2*1}=\frac{-16}{2}
=-8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+32}{2*1}=\frac{48}{2}
=24
$